Actually no. the key is above my two entries in GB's entry. Where I got the 1000 kg matrix (1000kg of Carbon/antimatter fullerene) to 1.4 kg antimatter. which gives 1 kg Matrix to 1.4 gram antimatter.
I assumed using 722 g for a complete Matrix for ease of not having to figure out in moles. Cause I did not want to dig out my physics and engineering mathematics equations books, which I have many.
So that is where I got 2.016g antimatter for the amount of 1.85 kg of explosive material for the warhead.
You don't figure out how many whole
mols are in use, you just need to know that the total mass is 722 units, and out of that mass 1 unit of it is antihydrogen. As an example, you could have 722 micrograms of fullerened antimatter, and of that mass only 1 microgram of it is antimatter. Or 1000 micrograms is fullerened antimatter, and 1.4 micrograms is the antimatter.
All you need to do is figure out the available warhead mass, divide that by 722, and that is the mass of antimatter. The only requirement is that the available warhead mass is greater than the mass of one of the fullerened antimatter
buckyballs (each is composed of 60 carbon atoms and one antihydrogen atom).
Mol mass is little more than adding up the atomic weights of all the atoms in a molecule, and saying that if you have
Avogadro's number of that molecule, the total mass of all those molecules will be equal to the sum of atomic weights expressed in grams. It is convenient for chemistry uses, but is not a minimum size (the true minimum size is one molecule of whatever you are measuring)
As an example, water's molar mass is ~18.015 g/mol (Hydrogen's atomic mass = 1.008, Oxygen's atomic mass = 15.999; 1.008+1.008+15.999 = 18.015). This does not mean you are unable to have less than ~18 g of water, it means that if you have a
mol of water molecules, it will mass ~18.015 grams. It does mean that if you have 1000 micrograms of water, and want to figure out how much hydrogen is present, you take the 1000 micrograms, divide it by 18.015, and multiply that by 2.016, telling you that there are 111.9 micrograms of hydrogen in 1000 micrograms of water.
If you want to calculate smaller amounts you can still subdivide that down to the level of individual water molecules.
I guess I will have to dig out those books to find what would be the minimum ability to carry on a warhead. Though that would come down to how small of a sample of the fullerene can be handled in a none science lab / industrial environment. I know these weapons would be made in a cleanroom since dealing with such small samples. But would you be using the same equipment to make the warhead filler insert as you initially used for the antimatter containment process into the fullerene?
Depends on the safety precautions, and how many mountains you want to make into craters. On the bright/glowing side, I'm sure some mining company wouldn't mind recommending that the government put the antimatter facility into a mountain that the mining company will eventually want to start mining (but have no way to cheaply deal with the overburden). If the antimatter filling plant works, you have a safe location to make munitions. If the antimatter plant has a hiccup, the mining company just got free demolition of the mountain they were planning on mining anyway.
Since it is the Kowloon Belters doing this, I could see the facility being built way out in the Oort cloud (2000+ AU) so nobody is nearby if it goes boom. The details of that facility though, it sounds like you have more experience about such designs.
