page 162 Interstellar Operations.
"A superheavy gyro weighs as much as a heavy-duty gyro
of equal capacity, and thus can be calculated by dividing the ’Mech’s
Engine Rating by 50 (and rounding up to the nearest whole number)."
This line gives 2 methods of calculating a super heavy mech's gyro.
Engine Rating / 50 rounded up to the nearest ton.
And
Engine rating/100 Rounded up to the nearest ton x 2 (Techmanual page 50)
Now let us assume a 175ton mech with a movement rating of 2/3. This gives an engine rating of 350.
350/50 = 7 tons.
350/100 = 3.5 round up to 4. 4x2 = 8 tons.
Which method is intended?
