Q1: Does the GM deploy a percent of the their total force or a percent of what the players field?
Pg. 6 states
"OpFor is always calculated using the tonnage of forces the players will field, it is never based off of the total force the players possess."
In the example though the GMs force is based on the total force and not what the players are fielding.
"The players are beginning a new campaign with the Meeting Engagement track, which allows them to field up to 33 percent of their total force. The players determine that their force comprises twelve ’Mechs totaling 580 tons. As tonnage must be used to balance the sides, 33% of their 580 tons may be fielded, equal to 191.4 tons, which rounds to 190 tons. They decide to use three ’Mechs, a Griffin, a Wolverine and a Catapult, with a combined mass of 175 tons.
The Defender in this track will be played by the GM; the Defender can also field up to 33 percent of their total force. The chooses to send in a Trebuchet, a Hunchback and his own Catapult, a total of 165 tons. The composition of the GM’s force would have allowed him to field four different ’Mechs which would have met the 33% cut off, but remember that he must field the same number of ’Mechs as the players—in this case, three."
If "OpFor is always calculated using the tonnage of forces the players will field", shouldn't the GM field 63 tons?
Q2: In Meeting Engagement, if the GM player is limited to 33% of the the player's fielded force, what happens if the players field one 20 ton unit?
