page 162 Interstellar Operations.

"A superheavy gyro weighs as much as a heavy-duty gyro

of equal capacity, and thus can be calculated by dividing the ’Mech’s

Engine Rating by 50 (and rounding up to the nearest whole number)."

This line gives 2 methods of calculating a super heavy mech's gyro.

Engine Rating / 50 rounded up to the nearest ton.

And

Engine rating/100 Rounded up to the nearest ton x 2 (Techmanual page 50)

Now let us assume a 175ton mech with a movement rating of 2/3. This gives an engine rating of 350.

350/50 = 7 tons.

350/100 = 3.5 round up to 4. 4x2 = 8 tons.

Which method is intended?