Register Register

Author Topic: (Answered) Superheavy Gyro mass vs Heavy Duty Gyro mass  (Read 352 times)

Thunder

  • Sergeant
  • *
  • Posts: 160
(Answered) Superheavy Gyro mass vs Heavy Duty Gyro mass
« on: 24 January 2019, 05:44:28 »
page 162 Interstellar Operations.
"A superheavy gyro weighs as much as a heavy-duty gyro
of equal capacity, and thus can be calculated by dividing the ’Mech’s
Engine Rating by 50 (and rounding up to the nearest whole number)."

This line gives 2 methods of calculating a super heavy mech's gyro.

Engine Rating / 50 rounded up to the nearest ton.

And

Engine rating/100 Rounded up to the nearest ton x 2  (Techmanual page 50)

Now let us assume a 175ton mech with a movement rating of 2/3.  This gives an engine rating of 350.
350/50 = 7 tons.
350/100 = 3.5 round up to 4.  4x2 = 8 tons.

Which method is intended?
« Last Edit: 22 July 2019, 16:25:50 by Xotl »

Thunder

  • Sergeant
  • *
  • Posts: 160
Re: (Research) Superheavy Gyro mass vs Heavy Duty Gyro mass
« Reply #1 on: 08 April 2019, 15:27:05 »
Quarterly (ish) bump.

Xotl

  • Deus Errata et regulas Exsecutor
  • Moderator
  • Lieutenant Colonel
  • *
  • Posts: 8948
  • Professor of Errata
Re: (Research) Superheavy Gyro mass vs Heavy Duty Gyro mass
« Reply #2 on: 22 July 2019, 16:25:45 »
It's supposed to be engine/100 (rounded up) ×2, as per TechManual.  The engine/50 formula was apparently made up for this passage as a quick (incorrect) shortcut.
« Last Edit: 22 July 2019, 18:46:05 by Xotl »
Generally absent from the forums at this time.

3028-3050 Random Assignment Tables -
Also contains faction deployment & rarity info and Quirk lists.

http://bg.battletech.com/forums/index.php?topic=1219.0

 

Register