Because I'm not sure what to believe

Because there are multiple possibilities that I have been presented

and more importantly

It would take you less effort to type out the correct way to deal those types of damage then to read and understand what I'd be trying to say.

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But if you *MUST* know:

TW says that Cluster (Ballistic) damage is dealt as Damage/10+1. That could either be sum damage, or dividing each cluster and rounding up.

**Examples: **

*LB-X 10 Cluster Round*

Total Warfare lists the formula, but gives no examples

**A)**Megamek calculates it as `((SUM DAMAGE)/10)+1`, for example `(10/10=1)+1=2`

**B)**TacOps, in the print version of the book under the section for Infantry Armor (Pg 317), lists an LB-X 10 Autocannon cluster round as doing 10+1 (11) damage, which could be put into a formula as `((Damage_for_individual_cluster/10, rounding up)*Number of Clusters)+1`.

**C)**Lastly, if you were to apply the calculation to each cluster hit, for example `(Individual Clusterhit/10, rounding up)+1)*Number of clusters`, an LB-X 20 could become particularly deadly against infantry, at 20 points of damage, even before dishing out any modifiers for being out in the open.

*SRM 6*

**A)**According to the example in Total Warfare, *20 LRMs* deal their full damage value, divided by 5, giving 4 points of damage. With this in mind, I'd expect SRMs to be the same way, so an SRM 6 has a maximum of 12 damage, divided by 5 making 2.4, rounded up to 3.

`(SumDamageofallmissiles/5, roundup). `

`(6*2=12)/5=2.4-->3`

**B)**However, playing Megamek gives a different calculation, in which rather than SRMs doing damage as per sum, it applies the division to each individual missile... causing six damage. In formulaic terms

`(Individual Cluster Hit of single missile/5, roundup)*clusters in volley`[/u], Or `((2/5=0.4-->1)*6=6`

If it were the way listed in "b", it would still agree with the example with the LRMs

`((5/5=1)*4=4`