BattleTech  The Board Game of Armored Combat
Catalyst Game Labs => BattleTech Game Rules Questions => Total Warfare => Topic started by: einherjarvalk on 04 February 2022, 00:00:00

TW and BMM both specify that when a 'Mech fails a DFA attack, damage is calculated as if the 'Mech had fallen 2 levels (regardless of attacker/defender elevation), always applied on the rear hit location table.
The standard formula for determining fall damage (of any sort) is 1 * (weight/10, rounded up) * (levels fallen + 1), meaning a 'Mech that falls over from something like a failed 20+ damage PSR would calculate as 1 * (weight/10, rounded up) * (0 + 1). Is my reading of the DFA rules correct in that a failed DFA would calculate as 1 * (weight/10, rounded up) * (2 + 1), or was the "2 level fall" intended to replace the "levels fallen + 1" part of the equation entirely?
The example I ran into tonight involved a Wolverine failing its DFA, which I calculated as 1 * (55/10 = ~6) * (2 + 1) = 18 damage, but I want to be completely sure it wasn't intended to be 1 * (55/10 = ~6) * (2) = 12 damage instead.

Fall damage is 1 per 10 tons (round up), multiplied by the number of levels fallen +1. For a DFA fall, that would result in a total modifier of x 3.
So a Wolverine would be 6 points, multiplied by 3, equalling 18.
In other words, no, the DFA rules were not meant to override the standard falling rules. The DFA rules say how many levels you fall, not what the multiplier is.