Interstellar Operations, 1st Printing, PDF
p130-131, Step 4: Add Armor
Change first paragraph from this:
Primitive JumpShips use the rules and limits for standard JumpShips when computing their armor values (see p. 152, SO), but may not mount any of the advanced armor types such as improved ferro-aluminum, ferro-carbide, or lamellor ferro-carbide. This means that the maximum tonnage of armor a Primitive JumpShip may carry is equal to the ship’s SI tonnage, divided by 12 (rounded down to the nearest half ton). In addition to this, as with modern JumpShips, Primitive JumpShips will receive additional “weight-free” armor points per facing, based on their structural integrity values.
To this:
Primitive JumpShips use the rules and limits for standard WarShips when computing their armor values (see p. 152, SO), and may not mount any of the advanced armor types such as improved ferro-aluminum, ferro-carbide, or lamellor ferro-carbide. This means that the maximum tonnage of armor a Primitive JumpShip may carry is equal to the ship’s SI tonnage, divided by 50 (rounded down to the nearest half ton). In addition to this, as with modern WarShips, Primitive JumpShips will receive additional “weight-free” armor points per facing, based on their structural integrity values. All armor mounted on a Primitive JumpShip—including the “free” armor provided by the vessel’s structural integrity value—must be multiplied by 0.66, rounding down to the nearest whole number.
Change the Armor example on p131 from this:
Reviewing the Advanced Aerospace Unit Armor Table let’s David know that he could assign a maximum of 83 tons of standard armor to his ship [1,000 (SI mass) ÷ 12 = 83.33, rounded down to 83]. He does not believe he’ll need anything close to that, and so decides he’s going to assign only 69 tons of Primitive armor.
Before placing the armor, he first determines how much “weight-free” armor the Aquilla will receive in addition to this, which is 1 point of capital-scale armor per facing, for a total of 6 points [10 (SI) ÷ 10 = 1 per facing; 6 facings x 1 point per facing = 6 points].
David then multiplies the 69 tons of armor he has opted for by the standard Advanced Aerospace Unit Armor Weights for a 100,000-ton Inner Sphere JumpShip using standard armor, and finds that this yields 55 armor points [69 (armor tonnage) x 0.8 (standard armor for a 100,000 vessel) = 55.2, rounding down to 55]. He then adds the free 6 points to 55 for a total of 61. Multiplying this total armor value by the Primitive armor factor of 0.66, he finds he has 40 armor points to allocate [61 (non-Primitive armor points) x .66 (Primitive armor factor) = 40.26, rounding down to 40].
He thus assigns this armor as follows: 9 to the nose, 7 to each fore-side, 6 to each aft-side and 5 to the aft.
This leaves a running total of 66,909 tons.
To this:
Reviewing the Advanced Aerospace Unit Armor Table let’s David know that he could assign a maximum of 20 tons of standard armor to his ship [1,000 (SI mass) ÷ 50 = 20, no rounding required]. Even though this is a low amount, he decides he’s going to assign only 19 tons of Primitive armor.
Before placing the armor, he first determines how much “weight-free” armor the Aquilla will receive in addition to this, which is 1 point of capital-scale armor per facing, for a total of 6 points [10 (SI) ÷ 10 = 1 per facing; 6 facings x 1 point per facing = 6 points].
David then multiplies the 19 tons of armor he has opted for by the standard Advanced Aerospace Unit Armor Weights for a 100,000-ton Inner Sphere WarShip using standard armor, and finds that this yields 15 armor points [19 (armor tonnage) x 0.8 (standard armor for a 100,000 vessel) = 15.2, rounded down to 15]. He then adds the free 6 points to 16 for a total of 21. Multiplying this total armor value by the Primitive armor factor of 0.66, he finds he has 13 armor points to allocate [21 (non-Primitive armor points) x .66 (Primitive armor factor) = 13.86, rounding down to 13].
He thus assigns this armor as follows: 3 to the nose, 2 to each fore-side, 2 to each aft-side and 2 to the aft.
This leaves a running total of 66,859 tons.
p131, Step 5: Complete Record Sheet
Change the last two paragraphs of the Complete Record Sheet example on p131 from this:
David then adds 20 escape pods, at 7 tons a piece, for a total of 140 tons. All of this gives him a running total of 79,798.
Finally, David takes the remaining tonnage and assigns it into 2 cargo bays of 10,101 tons each, with a single door for each cargo bay.
To this:
David then adds 20 escape pods, at 7 tons a piece, for a total of 140 tons. All of this gives him a running total of 79,748.
Finally, David takes the remaining tonnage and assigns it into 2 cargo bays of 10,126 tons each, with a single door for each cargo bay.
